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xs.yearMonthDuration.subtract

xs.yearMonthDuration.subtract(
   $value as xs.yearMonthDuration
) as xs.yearMonthDuration

Summary

Subtracts one xs.yearMonthDuration from another. Returns an xs.yearMonthDuration.

Parameters
$value A year month duration.

Example

const v1 = xs.yearMonthDuration("P3Y7M");
const v2 = xs.yearMonthDuration("P1Y4M");
v1.subtract(v2)

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